给定一个已排序的链表的头 head , 删除所有重复的元素,使每个元素只出现一次 。返回 已排序的链表 。
示例 1:
输入:head = [1,1,2]
输出:[1,2]
示例 2:
输入:head = [1,1,2,3,3]
输出:[1,2,3]
提示:
链表中节点数目在范围 [0, 300] 内
-100 <= Node.val <= 100
题目数据保证链表已经按升序 排列
/*** Definition for singly-linked list.* public class ListNode {* int val;* ListNode next;* ListNode() {}* ListNode(int val) { this.val = val; }* ListNode(int val, ListNode next) { this.val = val; this.next = next; }* }*/class Solution {public ListNode deleteDuplicates(ListNode head) {if (head == null) return null;ListNode tem = head;while (tem != null && tem.next != null) {//改变next指针if (tem.val == tem.next.val)tem.next = tem.next.next;elsetem = tem.next;}return head;}}
