解法一：数字统计+高精度

输入数据范围超过 long ，需要使用高精度。

import java.io.*;
import java.math.BigInteger;
import java.util.Arrays;
public class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));
        BigInteger N = new BigInteger(in.readLine());
        int[] res1 = parse(N);
        N = N.multiply(BigInteger.valueOf(2));
        int[] res2 = parse(N);
        if (Arrays.equals(res1, res2)) {
            out.println("Yes");
        } else {
            out.println("No");
        }
        out.println(N);
        out.flush();
    }
    private static int[] parse(BigInteger N) {
        int[] result = new int[10];
        while (!N.equals(BigInteger.ZERO)) {
            ++result[N.mod(BigInteger.TEN).intValue()];
            N = N.divide(BigInteger.TEN);
        }
        return result;
    }
}