解法一
转换成负进制和正进制大致相同,但注意余数始终为正,若不满足则可以修改商来补充余数。
class Solution {public String baseNeg2(int N) {if (N == 0) {return "0";}StringBuilder s = new StringBuilder();for (int base = -2, x; N != 0; ) {x = N % base;N /= base;// 余数始终非负if (x < 0) {++N;x -= base;}s.append(x);}return s.reverse().toString();}}
