void dfs(int[][] grid, int r, int c) {// 判断 base case// 如果坐标 (r, c) 超出了网格范围,直接返回if (!inArea(grid, r, c)) {return;}// 如果这个格子不是岛屿,直接返回if (grid[r][c] != 1) {return;}grid[r][c] = 2; // 将格子标记为「已遍历过」// 访问上、下、左、右四个相邻结点dfs(grid, r - 1, c);dfs(grid, r + 1, c);dfs(grid, r, c - 1);dfs(grid, r, c + 1);}// 判断坐标 (r, c) 是否在网格中boolean inArea(int[][] grid, int r, int c) {return 0 <= r && r < grid.length&& 0 <= c && c < grid[0].length;}
